by adem »
Wed Mar 07, 2007 7:24 pm
PLEASE BE AWARE THAT INSTALLING A NEW SHOWER CIRCUIT NEEDS CERTIFICATION UNDER PART P OF THE BUILDING REGULATIONS. FAILURE TO COMPLY CAN LEAD TO PROSECUTION AND RENDER YOUR HOUSE INSURANCE INVALID: DIYDOCTOR
may i ask where in bs7671 does it state a that a 16mm cable is needed for a 10.5 kw shower i woul d use following to caculate cable size
1. Determine the value of I B = Design Current.
IB = P
V
2. Select IN = Nominal current setting of the protective device (fuse, breaker etc.).
3. Calculate IZ = _______IN________
Ca x Ct x Cg x Ci
Ca – Factor for ambient temperature (4C1 + 4C2 p 219)
Ct = Operating temperature of conductor (Bs 3036 x 0.725)
Cg = Factor for grouping (4B1 – 4B3 p217)
Ci = Factor for thermal insulation
4. After calculating Iz select a cable from 4D1A – 4LB4 p220
5. Calculate volt drop (max. permissible vd = 4%, 9.2 for 230V)
Vd = L x Ib x mV/A/m
1000
L = Length of run
Ib = Design Current
mV/A/m = 4D1A – 4L4B
6. Establish tabulated maximum permissible value of ZS from tables 41B1, 41B2, 41C, 41D – p46
7. Calculate ZS
ZS = Ze + (R1 + R2 x L x t)
R1 + R2 = On site guide 9A P158
L = Length of run
T = On site 9B, 9C p159
8. Calculate the maximum earth fault current.
If = Uo
Zs
If = Fault current
Uo = Nominal voltage
Zs = Actual Zs value
9. Check disconnection time of protective device ( Appendix 3 p194-201)
10. Calculate minimum size of cpc.
_____
S = √ I2 t S = Minimum size of cpc
K I2 = Max. earth fault current
T = Disconnection time
K = Factor for resistivity and temperature (54B – 54E p115)
hope this helps :D